How do you express #ln(t+4) = -1# in exponential form ?

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Answer 1 · 2017-12-05T04:21:45

#t= e^-1-4#
[#t approx -3.63212#]

#ln(t+4) = -1#

Remember: #lnx = a -> x = e^a#

Hence, in our example, #t+4 = e^-1#

#t= e^-1-4#

Since we are asked for the equation in exponential form, the equation above is the answer.

N.B. This equation can be solved to give an approximate value of #t#. We can only ever obtain an appxoximate result as #e# is irrational.

#t approx 0.367879 - 4#

#t approx -3.63212#