Question #875ac

1 Answer

Answer:

Using various properties of a mol, the volume of one #"Hg"# atom is #"2.44895 * 10^-23# #"cm"^3#.

Explanation:

First, let's determine the overall volume of one mole of #"Hg"#. The molar mass of #"Hg"# is #"200.6 g/mol"#, so there are #"200.6 g"# of #"Hg"# in one mole of #"Hg"#.

We know the number of atoms in one mole, so we'll use #"200.6 g"# as mass. The formula for density is :

#d=m/V#

Switching between the variables will leave us with this:

#V=m/d#

Substitute the values:

#"200.6 g"/"13.6 g/cm"^3 = V#

And you get the volume of one mole as #"14.75 cm"^3#. The number of atoms in one mol is #6.022 * 10^23# atoms. Divide the volume by the number of atoms to get #2.44895 * 10^-23# #"cm"^3#.