# Question 875ac

Dec 5, 2017

Using various properties of a mol, the volume of one $\text{Hg}$ atom is "2.44895 * 10^-23# ${\text{cm}}^{3}$.

#### Explanation:

First, let's determine the overall volume of one mole of $\text{Hg}$. The molar mass of $\text{Hg}$ is $\text{200.6 g/mol}$, so there are $\text{200.6 g}$ of $\text{Hg}$ in one mole of $\text{Hg}$.

We know the number of atoms in one mole, so we'll use $\text{200.6 g}$ as mass. The formula for density is :

$d = \frac{m}{V}$

Switching between the variables will leave us with this:

$V = \frac{m}{d}$

Substitute the values:

${\text{200.6 g"/"13.6 g/cm}}^{3} = V$

And you get the volume of one mole as ${\text{14.75 cm}}^{3}$. The number of atoms in one mol is $6.022 \cdot {10}^{23}$ atoms. Divide the volume by the number of atoms to get $2.44895 \cdot {10}^{-} 23$ ${\text{cm}}^{3}$.