Question #2c774

1 Answer
Dec 5, 2017

Answer:

Roughly #2491kg#

Explanation:

The reaction between #Mg# and #O_2# to produce #MgO# goes like this:

#2Mg_((s))+O_(2(g))->2MgO_((s))#

#4131kg=4131000g#

#n(MgO)=4131000/(24.3+16)=102506.2035mol#

Molar ratio of Mg:MgO is 1:1

So, #102506.2035mol# of #Mg# are needed.

#M_r(Mg)=24.3#

#m=n*M_r=24.3(102506.2035)=2490900.744kg=2490.900744g~~2491kg#