Question #bcce3

1 Answer
P dilip_k
Dec 5, 2017

#RHS=(csc(theta))/(csc(theta)-2sin(theta)#

#=(csc(theta)sin(theta))/(csc(theta)*sin(theta)-2sin^2(theta)#

#=(1/sin(theta)sin(theta))/(1/sin(theta)*sin(theta)-2sin^2(theta)#

#=1/(1-2sin^2(theta)#

#=1/(cos2(theta)#

#=sec2(theta)=LHS#

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