Question #b4df7

1 Answer
Dec 6, 2017

#LHS=(1+cos\theta +sin\theta )/(1+cos\theta -sin\theta )#

#=(costheta(1+cos\theta +sin\theta ))/(costheta(1+cos\theta -sin\theta ))#

#=(costheta+cos^2\theta +costhetasin\theta )/(costheta(1+cos\theta -sin\theta ))#

#=(costheta+1-sin^2\theta +costhetasin\theta )/(costheta(1+cos\theta -sin\theta ))#

#=(costheta(1+sintheta)+(1-sintheta )(1+sintheta) )/(costheta(1+cos\theta -sin\theta ))#

#=((1+sintheta)(costheta+1-sintheta ))/(costheta(1+cos\theta -sin\theta ))#

#=(1+sin\theta )/(cos\theta )=RHS#