Question

Question #84ccb

Answer 1

See a solution process below:

Explanation:

First, using the standard order of operation or PEDMAS, execute the operations with the Parenthesis first:

`1 xx (color(red)(50) + color(red)(1779)) -: (color(blue)(81) -: color(blue)(9)) =>`

`1 xx 1829 -: 9`

Next, execute the Multiplication and Division operations left to right:

`color(red)(1) xx color(red)(1829) -: 9 =>`

`color(red)(1829) -: color(red)(9) =>`

`color(red)(1829)/color(red)(9) =>`

`(1827 + 2)/9 =>`

`1827/9 + 2/9 =>`

`203 + 2/9 =>`

`203 2/9`

or

`203.2222....`

or

`203.bar2`