# Question #03e8d

pH = 10

#### Explanation:

To solve this there are a few things you need to know

pH = -log[H+]
pOH = -log[OH-]

pH + pOH = 14

Since you are given the concentration of hydroxide [OH-] = $1 x {10}^{- 4}$ M you can calculate that the pOH is 4 by taking the negative log of the [OH-] concentration.

Since pOH = 4, the pH must be 10

14 - pOH = pH
14 - 4 = 10

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Hope this helps!