Question #f9a90

1 Answer
Dec 7, 2017

#arcsin(3/5)+arctan(1/7)=pi/4#

Explanation:

Set #arcsin(3/5)=a# and #arctan(1/7)=b#, so #sina=3/5#, #tana=3/4# and #tanb=1/7#

Hence,

#tan(a+b)=(tana+tanb)/(1-tana*tanb)#

=#(3/4+1/7)/(1-3/4*1/7)#

=#(25/28)/(25/28)#

=#1#

Thus, #a+b=arcsin(3/5)+arctan(1/7)=pi/4#