# Question #a1812

Dec 9, 2017

$2$ moles ${\text{NH}}_{3}$.
The equation states that for $3$ moles of ${\text{H}}_{2}$, it yields $2 {\text{NH}}_{3}$. However, the proper ratio would be $1 : 3 : 2$.
${N}_{2} + 3 {H}_{2} \to 2 N {H}_{3}$
$\text{N = 2 atoms + H = 6 atoms " -> " N = 2 atoms + H = 6 atoms}$