Question #d2c51

1 Answer
anor277
Dec 8, 2017

You have left us to guess at the question....

Explanation:

You got #C_4H_10O#, which COULD be #"diethyl ether"# #(H_5C_2)_2O#, or #"methyl isopropyl ether"# #H_3C(H_7C_3^(i))O#...or other isomers of the alcohol. #"Isopropyl ethers"# are generally not present in any teaching laboratory, as they tend to be highly reactive customers because of radical formation....

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