Question #96b84

1 Answer
turksvids
Dec 8, 2017

The angle is #(4pi)/3# or #-(2pi)/3#.

Explanation:

Since the #r# value is correct you can tell the computer wants you to distribute the negative inside the parentheses: #6pi(-1/2-isqrt(3)/2)#, the ordered pair #(-1/2,-sqrt(3)/2)# corresponds to an angle of #(4pi)/3#. It looks like the program also wants the negative coterminal, so #-(2pi)/3#.

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