Question #7e1a8

1 Answer
Dec 11, 2017

#"see explanation"#

Explanation:

#•color(white)(x)sintheta=y/r" and "costheta=x/r#

#•color(white)(x)r=sqrt(x^2+y^2)rArrr^2=x^2+y^2#

#rArrsin^2theta+cos^2theta#

#=(y/r)^2+(x/r)^2#

#=y^2/r^2+x^2/r^2#

#=(x^2+y^2)/r^2=r^2/r^2=1#