Question #7e1a8
1 Answer
Dec 11, 2017
Explanation:
#•color(white)(x)sintheta=y/r" and "costheta=x/r#
#•color(white)(x)r=sqrt(x^2+y^2)rArrr^2=x^2+y^2#
#rArrsin^2theta+cos^2theta#
#=(y/r)^2+(x/r)^2#
#=y^2/r^2+x^2/r^2#
#=(x^2+y^2)/r^2=r^2/r^2=1#