Question #93a73

1 Answer
Dec 11, 2017

#x=+-3#

Explanation:

Consider for a moment log to base 10 where we have:

#log_10(x)=y#

This is the same as #10^y=x#

Now directly compare the structure to #log_(2x)(36)=2#

This has to be: #(2x)^2=36#

Thus #2x=+-sqrt(36) = +-6#

Thus #x=+-3#