Question #117e2

1 Answer
Al E.
Feb 22, 2018

Consider your situation,

dev.physicslab.org

, and apply Newton's laws,

#SigmaF_y = F_N + Fsintheta - mg = 0#

#=> F_N = mg - Fsintheta#

#SigmaF_x = Fcostheta - F_"fr" = 0#

#=> Fcostheta - mu_k * (mg - Fsintheta) = 0# (constant #vec a#)

Hence,

#=> -mu_k = (-Fcostheta)/(mg-Fsintheta) => mu_k approx 0.609#

is the kinetic friction coefficient between the box and the table.

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