#vecb=-4/sqrt13hati+6/sqrt13hatj# or #vecb=4/sqrt13hati-6/sqrt13hatj#
Explanation:
Let #vecb=xhati+yhatj# and as #veca=6hati+4hatj#
Then #veca*vecb=6x+4y#, but as #veca# and #vecb# are orthogonal their dot product should be #0# i.e. #6x+4y=0# or #6x=-4y# or #x=-2/3y# i.e.#vecb=-2/3yhati+yhatj# and hence #|b|=sqrt((4y^2)/9+y^2)=sqrt((13y^2)/9)#
As #|b|=2#, #(13y^2)/9=4#
or #y=+-6/sqrt13# and #x=∓4/sqrt13#
Hence #vecb=-4/sqrt13hati+6/sqrt13hatj# or #vecb=4/sqrt13hati-6/sqrt13hatj#