Question #2cdcb

1 Answer
Rhys
Dec 13, 2017

#x = 3/2 #

Explanation:

We must use our log laws:

#log alpha - log beta = log(alpha/beta) #

So we can write it as:

#=> log( (2x+3)/8 ) = log(x/2) #

Using another log law:

#a^(log_a x ) = x #

#=> 10^(log( (2x+3) / 8 ) ) = 10^log(x/2) #

#=> (2x+3)/8 = x/2 #

#=> 2x+3 = 4x #

#=> 3 = 2x #

#=> x = 3/2 #

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