Question

Complete combustion of a `17.4*g` mass of propane would give rise to WHAT VOLUME of carbon dioxide at `1*atm` pressure, and `298*K` temperature?

Answer 1

Well, first we specify that `1*mol` of Ideal Gas occupies a volume of `24.5*L`....at `1*atm` pressure and `298*K`....

Explanation:

We gots the stoichiometric equation....

`C_3H_8 + 5O_2(g) rarr 3CO_2(g) +4H_2O(l)`

Note that as written I gots the water as a LIQUID, but then again the question asked us to predict the volume that the carbon dioxide would occupy.

`"Moles of propane"-=(17.4*g)/(44.10*g*mol^-1)=0.395*mol`

And so volume of carbon dioxide evolved.....

`0.395*molxx3xx24.5*L*mol^-1=29.0*L`