Question

Question #91c57

Answer 1

Let `x/2 = y`

Then `x = 2y`. Substituting, we get:

`sin(2y) = 2sinycosy`

This is true because `sin(A + B) = sinAcosB + sinBcosA`.

Repeat the same for the second problem and you will see it is true as well

Hopefully this helps!