If #secu=-6#, find #sin(u/2),cos(u/2)# and #tan(u/2)#?

1 Answer

See below.

Explanation:

Using following identities:

#color(red)(tanx=sinx/cosx)#

#color(red)(cos^2(x/2)=1/2(1+cos(x)))#

#color(red)(sin^2(x/2)=1/2(1-cos(x)))#

#color(red)(secx=1/cosx)#
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Observe that as #u# is in #Q2#, #u/2# is in #Q1# and all trigonometric ratios of #u/2# are positive.

#sec(u)=1/cos(u)#

#:.#

#1/cos(u)=-6# , #cos(u)=1/-6#

#color(green)(cos(u/2))=sqrt(1/2(1+cos(u)))=sqrt(1/2(1-1/6))=color(blue)(sqrt(5/12))#

#color(green)(sin(u/2))=sqrt(1/2(1-cos(u)))=sqrt(1/2(1-(-1/6)))=color(blue)(sqrt(7/12))#

#color(green)(tan(u/2))=sin(u/2)/cos(u/2)=(sqrt(7/12))/(sqrt(5/12))=color(blue)((sqrt(35))/5)#