Question #853fd

1 Answer
Dec 15, 2017

#2sin5alpha+2sinalpha#

Explanation:

#"using the "color(blue)"product to sum formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(2sinAcosB=sin(A+B)+sin(A-B))color(white)(2/2)|)))#

#"here "A=3alpha" and "B=2alpha#

#rArr4sin3alphacos2alpha#

#=2(2cos3alphacos2alpha)#

#=2[sin(3alpha+2alpha)+sin(3alpha-2alpha)]#

#=2sin5alpha+2sinalpha#