# Question #dd1a6

The equation is just work done, $w = F \times s$ provided the force applied is in the direction of the displacement, s. So if a workman pulls a tool 0.5m towards him with a force of 8N the work done is: $w = F \times s = 8 \times 0.5 = 4 N m$ Just be careful to use distance in m even if it is quoted in cm or km in the question.
At a higher level, we introduce the idea that the force could be at an angle to the displacement (e.g. a dog pulling it’s owner on a lead), in which case we use $w = F \times s \times \cos \theta$ where $\theta$ is the angle between them. This means no work is done if the force is a right angles to the displacement travelled.