Question #8e0ca

1 Answer
Dec 15, 2017

136.25 grams


We need to write a balanced equation for the formation of ammonia from nitrogen:

#N_2 + 3H_2 -> 2NH_3#

Nitrogen and ammonia are in a 1 : 2 ratio i.e. for every mole of nitrogen used, two moles of ammonia are produced.

Since we used 4 moles of nitrogen in this reaction, 8 moles of ammonia are produced (4 x 2).

Now we just need to convert the number of moles of ammonia into the mass of ammonia.

We do this using the following equation:
Mass (g) = Mr (g/mol) x Number of Moles (mol)

Mr ammonia = 17.031 g/mol

Mass = 17.031 x 8
Mass = 136.25 g