Solve for #x# given that: #10/12 = (x - 5)/6# ?

2 Answers
Dec 23, 2017

Please see the step process below;

Explanation:

#10/12 = (x - 5)/6#

Cross multiply..

#10 xx 6 = 12 (x - 5)#

#60 = 12x - 60#

Collect like terms..

#60 + 60 = 12x#

#120 = 12x#

Divide both sides by #12#

#120/12 = (12x)/12#

#120/12 = (cancel12x)/cancel12#

#120/12 = x#

#10 = x#

#x -> 10#

Hope this helps!

Dec 23, 2017

#x=10#

Explanation:

To maintain proportionality in a fraction or ratio what you do to the bottom you also do to the top for multiply or divide. Does not work for add or subtract.

We need to be able to change the 12 from #10/12# into 6

#(10-:2)/(12-:2)=(x-5)/6#

#(5)/(6)=(x-5)/6#

As the denominators (bottom numbers) are the same we may #ul("directly")# compere the numerators (top numbers).

#color(green)(5=x-5)#

Add #color(red)(5)# to both sides

#color(green)(5color(red)(+5)=x-5color(red)(+5))#

#10=x+0#

#x=10#