Question #d351f

1 Answer

Answer:

#"0.075 moles"# or #"6.75 grams"#.

Explanation:

Consider this molarity equation:

#"no. of moles"/"volume in Liters" = "Molarity"#

First, convert #"mL"# to #"L"# #-># #"750mL = 0.75L"#

Since you are given the volume and the molarity, plug them into the equation and find the number of moles of oxalic acid required:

#"no. of moles"/("0.75 L") = "0.1 M" -> "no. of moles" = "0.075 mol"#

If you want the amount of oxalic required in grams, then you use dimensional analysis to convert from moles to grams:

#("0.075 mol oxalic acid") * ("90 g oxalic acid"/"1 mol oxalic acid") = "6.75 g oxalic acid required"#

I hope that helps!