# Question d351f

Dec 16, 2017

$\text{0.075 moles}$ or $\text{6.75 grams}$.

#### Explanation:

Consider this molarity equation:

$\text{no. of moles"/"volume in Liters" = "Molarity}$

First, convert $\text{mL}$ to $\text{L}$ $\to$ $\text{750mL = 0.75L}$

Since you are given the volume and the molarity, plug them into the equation and find the number of moles of oxalic acid required:

$\text{no. of moles"/("0.75 L") = "0.1 M" -> "no. of moles" = "0.075 mol}$

If you want the amount of oxalic required in grams, then you use dimensional analysis to convert from moles to grams:

("0.075 mol oxalic acid") * ("90 g oxalic acid"/"1 mol oxalic acid") = "6.75 g oxalic acid required"#

I hope that helps!