Question

Question #1c906

Answer 1

`LHS=((2n)!)/(n!)`

`=(2n(2n-1)(2n-2)......4*3*2*1)/(n!)`

`=(2^n*(n(n-1)(n-2)4*3*2*1))/(n!)xx(2n-1)(2n-3)........5×3×1`

`=2^n*(n!)/(n!)xx(2n-1)(2n-3)........5×3×1`

`=2^n(2n-1)(2n-3)........5×3×1`