Under standard conditions, what volume of carbon dioxide would result from the combustion of #295*g# of #"propane"#?
We need to write a stoichiometrically balanced equation. And for combustion reactions the usually rigmarole is to (i) balance the carbons as carbon dioxide; (ii) then balance the hydrogens as water, and (iii) then balance the oxygens.
Even-numbered alkanes require a half-integral coefficient for dioxygen....
And thus, upon complete combustion, we gets
At STP, if the molar volume is
The chemical equation for the combustion of propane:
Since there's an excess of oygen, propane gas is the limiting reactant. Using dimensional analysis, find how many liters of carbon dioxide are produced:
(1mol = 22.4L @ STP)
* ( 3mol