Question #c8563

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Answer 1 · 2017-12-18T13:25:18

#x^2+y^2=1#

we need the transformation eqns

#r^2=x^2+y^2--(1)#

#x=rcostheta--92)#

#y=rsintheta--(3)#

we have

#r=1#

#=>r^2=1#

using#(1)#

#x^2+y^2=1#

which is a circle centre

#(0,0)#

radius #r=1#

graph{x^2+y^2=1 [-10, 10, -5, 5]}