Question #5cb4b

1 Answer
Dec 18, 2017

Given: #cos(x) - sqrt2/2 = sin(x), 0^@ <= x <= 360^@#

Add #sqrt2/2-sin(x)# to both sides:

#cos(x)-sin(x) = sqrt2/2, 0^@ <= x <= 360^@#

Multiply both sides by #sqrt2/2#

#sqrt2/2cos(x)-sqrt2/2sin(x) = 1/2, 0^@ <= x <= 360^@#

Use the identity #cos(A+B)= cos(A)cos(B)-sin(A)sin(B)# where #A = x# and #B = 45^@# (because sin(45^@) = cos(45^@) = sqrt2/2):

#cos(x+45^@) = 1/2, 0^@ <= x <= 360^@#

#x+45^@ = cos^-1(1/2), 0^@ <= x <= 360^@#

#x +45^@ = 60^@# and #x + 45^@= 300^@#

#x = 15^@# and #x = 255^@#