Question #c11fc
3 Answers
Dec 19, 2017
Image reference..
Explanation:
Dec 19, 2017
Explanation:
#"using the "color(blue)"trigonometric identities"#
#•color(white)(x)sin^2x+cos^2x=1#
#•color(white)(x)tan^2x=sec^2x-1#
#"consider the left hand side"#
#(1-cos^2x)/(sec^2x-1)#
#=sin^2x/tan^2x#
#=(sin^2x)/(sin^2x/cos^2x)#
#=cancel(sin^2x)xxcos^2x/cancel(sin^2x)#
#=cos^2x=" right hand side "rArr"verified"#
Dec 19, 2017
Explanation:
#"using the "color(blue)"trigonometric identities"#
#•color(white)(x)sin^2x+cos^2x=1#
#•color(white)(x)sec^2x=1/cos^2x#
#"consider the left hand side"#
#(1-cos^2x)/(sec^2x-1)#
#=(sin^2x)/(1/cos^2x-1)#
#=(sin^2x)/((1-cos^2x)/cos^2x)#
#=(sin^2x)/(sin^2x/cos^2x)#
#=cancel(sin^2x)xxcos^2x/cancel(sin^2x)#
#=cos^2x=" right hand side "rArr"verified"#