#"=P[both red] + P[both white]"#
#=P["marble box A is red"] * P["marble box B is red"] +#
#P["marble box A is white"] * P["marble box B is white"]#
#= (5/8)(2/8) + (3/8)(6/8)#
#= (10 + 18)/64#
#= 7/16#
#"Further explanation :"#
#"P[both red OR both white] = P[both red ] + P[both white]"#
#"- P[both red and white] , but P[both red and white] = 0 as"#
#"the balls cannot have two colors."#
#"P[ both red ]= P[ marble box A is red ] * P[ marble box B is red ]"#
#"because the drawings from both boxes are independent and for"#
#"independent events we have : "P[A and B] = P[A] * P[B]#
#"To calculate the chance that a marble from a certain box has"#
#"a certain color, we count the number of marbles, which is 8"#
#"in both boxes, and count how many of that total have the color"#
#"in question."#
