Question #6e2a4
2 Answers
Dec 21, 2017
See the answer below....
Explanation:
#sectheta-sintheta cdot tantheta#
#=1/costheta-sintheta cdot sintheta/costheta#
#=(1-sin^2theta)/costheta#
#=cos^2theta/costheta# [#"as "sin^2theta+cos^2theta=1# ]
#=costheta#
Proved
Hope it helps....
Thank you...
Dec 21, 2017
Explanation:
#"using the "color(blue)"trigonometric identities"#
#•color(white)(x)sin^2x+cos^2x=1#
#•color(white)(x)secx=1/cosx" and "tantheta=sintheta/costheta#
#"consider the left hand side"#
#sectheta-sinthetatantheta#
#=1/costheta-sinthetaxxsintheta/costheta#
#=1/costheta-sin^2theta/costheta#
#=(1-sin^2theta)/costheta=cos^2theta/costheta#
#=(cancel(costheta)costheta)/cancel(costheta)#
#=costheta=" right hand side "rArr"proven"#