# Question #b18b1

##### 1 Answer

*Your answer is given below:*

#### Explanation:

*The initial velocity given in the question is*,

**The throwing angle**,

*The mentioned height from ground*,

**We know that,**

*then the distance from the throwing point to the hitting point of the projectile,*

*then the distance from the throwing point to the hitting point of the projectile, #x=833.08m.#*

So,*The building will be #192.7m or 833.08m # far from the throwing point*

**As a projectile moves in semi- circular way, its height from the ground would same for two different times**

*You also want the tallest building that the projectile could clear. It means the highest height #color(red)('H')# of the projectile from the ground*

we know,