Question #6c90e

2 Answers
Sunayan S
Dec 23, 2017

Image reference...

Explanation:

my notebook....

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Thank you...

P dilip_k
Dec 23, 2017

#LHS=(cos2theta)/(1+sin2theta)#

#=(cos^2theta-sin^2theta)/(cos^2theta+sin^2theta+2sinthetacostheta)#

#=((costheta-sintheta)(costheta+sintheta))/(costheta+sintheta)^2#

#=(costheta-sintheta)/(costheta+sintheta)#

#=(costheta/sintheta-sintheta/sintheta)/(costheta/sintheta+sintheta/sintheta)#

#=(cottheta-1)/(cottheta+1)=RHS#

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