If the zeros of #3x^2+5x-2# are #alpha# and #beta#, then what quadratic has zeros #2alpha# and #2beta# ?
2 Answers
Dec 24, 2017
Explanation:
We can factorise
For this to equal 0, either
We will call
So,
By expanding, we get:
Dec 24, 2017
Explanation:
Substituting
#3x^2+5x-2 = 3(t/2)^2+5(t/2)-2#
#color(white)(3x^2+5x-2) = 3/4t^2+5/2t-2#
Multiplying through by
#3t^2+10t-8#
or using
#3x^2+10x-8#