Question #a3a72

1 Answer
Dec 25, 2017

#(a): (foj)(x); (b): (go(foh))(x); (c): (jo(gof))(x)#.

Explanation:

(a):

#f(x)=x-2 rArr f(3x)=3x-2#.

#:. y=3x-2=f(3x)=f(j(x))=(foj)(x)#.

(b):

#f(x)=x-2 rArr f(x^3)=x^3-2, i.e., f(h(x))=x^3-2, or#,

#(foh)(x)=x^3-2=u," say"#.

#g(x)=sqrtx rArr g(u)=sqrtu=sqrt(x^3-2)#.

#:. y=sqrt(x^3-2)=g((foh)(x))=(go(foh))(x)#.

(c):

Try Yourself and get, #y=(jo(gof))(x)#.