How might #"2-butyne"# be prepared from #"1-propyne"# and #"methyl iodide"#?

1 Answer
anor277
Dec 27, 2017

Well, terminal acetylenes are acidic....and so we could start with #"propyne..."#, #HC-=C-CH_3#...

Explanation:

And thus....

#H_3C-C-=CH+Pr_2^(i)N^(-)Li^+ rarrH_3C-C-=C^(-)Li^(+) + Pr_2^(i)NH#

#H_3C-C-=C^(-)Li^(+) + H_3C-ClrarrH_3C-C-=C-CH_3 +LiCl(s)darr#

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