Question

Question #ed14b

Answer 1

No solution for `tin ℝ`

Explanation:

`csc^2(t-4)=0`

`csc(t-4)=0`

Solution 1: `t-4=csc^-1(0)+2pin`

`t=csc^-1(0)+2pin+4`

Solution 2: `t-4=pi+csc^-1(0)+2pin`

`t=pi+csc^-1(0)+2pin+4`

Because the function `csc(0)=1/sin(0)`, and `1/sin(0)` is undefined, therefore there is no value for `sin^-1(0)` and it follows, there is no value for `csc^-1(0)`.

There is `csc^-1(0)` in both solutions, so that means there is no solution for `tin ℝ`.