Question

Question #953d9

Answer 1

`2log_10(5)~~1.4`

Explanation:

`log 25`

`=log_10(25)`

`=log_10(5^2)`

Applying the log rule (`log_a(x^b)=blog_a(x)`)

`=2log_10(5)`

`=1.39794...~~1.4`