Question #9e86d

1 Answer
P dilip_k
Dec 30, 2017

Given #sintheta-costheta=7/13.....(1)#

#(sintheta+costheta)^2+(sintheta-costheta)^2=2(sin^2theta+cos^2theta)#

#=>(sintheta+costheta)^2+(7/13)^2=2*1#

#=>(sintheta+costheta)^2=2-49/169=289/169=17^2/13^2#

#=>sintheta+costheta=17/13....(2)#

Adding (1) and (2) we get

#2sintheta=24/13#

#=>sintheta=12/13#

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