Question #a8fbe

1 Answer
Jan 4, 2018

#10^(1.5335)#

Explanation:

We know #log(3416) = 3.5335# so we can exponentiate and find:

#10^3.5335=3416#

Divide both sides by 100 to get:

#10^3.5335/100=3416/100#

which gives:

#34.16 = 10^3.5335/10^2#

using properties of exponents we have:

#34.16 = 10^(3.5335-2)#

#34.16 = 10^(1.5335)#, which might be what you're looking for but I'm not sure what form the answer should take.