Question #c0fe0
1 Answer
Jan 5, 2018
Explanation:
#"using the "color(blue)"trigonometric identity"#
#•color(white)(x)sin2x=2sinxcosx#
#"consider the left hand side"#
#1-2cos^2xsin^2x#
#"take out a common factor of "1/2#
#=1/2(2-4cos^2xsin^2x)#
#=1/2[2-(2sinxcosx)(2sinxcosx)]#
#=1/2[2-(sin2x)(sin2x)]#
#=1/2[2-sin^2(2x)]=" right hand side"#
