Question #71efa

1 Answer
Alan P.
Jan 5, 2018

#P(E^1|E^2)=1/6#

Explanation:

Given #E^2# i.e. that the first die is a 3
of the 6 possible values for the second die, exactly 1 of them, namely the second die face is a 5, results in #E^1#

(There is some variation is notation usage but I assumed #P(E^1|E^2)# means the probability of #E^1# given #E^2#.)

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