Question #afbd9

2 Answers
Jim G.
Jan 7, 2018

#x=e^(-2)-5#

Explanation:

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)log_bx=nhArrx=b^n#

#rArr2ln(x+5)=-4#

#rArrln(x+5)=-2#

#[lnx=log_ex]#

#rArrx+5=e^(-2)#

#rArrx=e^(-2)-5~~-4.865" to 3 dec. places"#

Somebody N.
Jan 7, 2018

See below.

Explanation:

#2ln(x+5)=-4#

#ln(x+5)=-2#

Taking antilogarithms:

#e^(ln(x+5))=e^(-2)#

#x+5=e^(-2)=>x=e^(-2)-5~~-4.8647#

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