Question #efacf

1 Answer
Jan 8, 2018

#theta#=60#degrees or #pi/3#radians

Explanation:

#cot(theta)=sqrt(3)/3#

#cot(x)=1/tan(x)#

#=>1/tan(x)=sqrt(3)/3#

Taking reciprocal on both sides

#tan(theta)=3/sqrt(3)=sqrt(3)#

#=>theta=arctan(sqrt(3))=60#degrees or #pi/3#radians