Question #ce570

1 Answer
Jan 8, 2018

#coth(ln(x))=(x^2+1)/(x^2-1)#

Explanation:

#coth(lnx)=1/(tanh(lnx))#

#=cosh(ln(x))/(sinh(ln(x))#

#=((1/2)(e^(lnx)+e^(-lnx)))/((1/2)(e^(lnx)-e^(-ln(x))))#

#=(e^(lnx)+e^(ln(1/x)))/(e^(lnx)-e^(ln(1/x))#

#=(x+(1/x))/(x-(1/x))#

#=((x^2+1)/x)/((x^2-1)/x)#

#=(x^2+1)/(x^2-1)#