Question

Question #3317a

Answer 1

`LHS=sqrt ((1-cos theta)/(1+cos theta))`

`=sqrt (((1-cos theta)(1+costheta))/(1+cos theta)^2)`

`=sqrt ((1-cos^2 theta)/(1+cos theta)^2)`

`=sqrt (sin^2 theta/(1+cos theta)^2)`

`=sin theta/(1+cos theta)=RHS`