If #tantheta = sqrt(3)#, then how would you find the value of #sintheta#?

1 Answer
Jan 8, 2018

#sintheta = sqrt(3)/2#

Explanation:

We know that #tan^2theta + 1 = sec^2theta#, thus:

#sec^2theta = (sqrt(3))^2 + 1 = 4#

Thus #sectheta = 2#, and since secant is the reciprocal of cosine, #costheta = 1/2#.

We know that #tantheta = sintheta/costheta#, thus #sintheta = tanthetacostheta#.

#sintheta = 1/2(sqrt(3)) = sqrt(3)/2#

Hopefully this helps!