# Question #5d67b

Jan 15, 2018

$5 u n i t s$

#### Explanation:

Let us make a graph of speed$\left(v\right)$ vs time$\left(t\right)$

so,our equation becomes $v$ = $| t - 3 |$ (because speed is never negative)

so,our table becomes,
at, $t = 0 , v = 3$
$t = 1 , v = 2$
$t = 2 , v = 1$
$t = 3 , v = 0$
$t = 4 , v = 1$

Now putting the values in the graph, we get a curve.

we know that distance = area under( speed-time) curve

so,area under the curve we obtained is,
$\frac{1}{2} \cdot 3 \cdot 3 + \frac{1}{2} \cdot 1 \cdot 1$ or, $5 u n i t s$