Question #da76e

$4 x$
Remember the power rule: If $f \left(x\right) = {x}^{b}$, then $f ' \left(x\right) = b {x}^{b - 1}$
$f \left(x\right) = 2 {x}^{2}$
$f ' \left(x\right) = \left(2 {x}^{2}\right) ' = 2 \cdot 2 x = 4 x$