Question #31f43

1 Answer
Jan 16, 2018

6.874 m/s^2 about 71.90 degrees w.r,t north

Explanation:

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15 N force is acting along south and 50N along northeast. So total force acting along north is 50cos 45 or,35.35 N,so net force acting along north is (35.35-14) or,21.35N

And force acting along east is (50 cos 45+30) or,65.35N.

so,let ,net force acting along theta degrees w.r,t North and its magnitude is sqrt(21.35^2+65.35^2) N or,68.74 N

tan theta = 65.35/21.35 or, theta= 71.90 degrees

so,magnitude of acceleration will be 68.74/10 or 6.874m/s^2 along the direction of net force.